• Matéria: Matemática
  • Autor: adrianesalvar
  • Perguntado 9 anos atrás

Resolver esse sistema : 
-3x - 2y =8
x-5y=3

Respostas

respondido por: geraldomiron
1
-3x-2y=8
x-5y=3 multiplico ambos termo por 3

-3x-2y=8
3x-15y=9
0x -17y=17
y=-1
x=-2
respondido por: LuanaSC8
1
 \left \{ {{-3x-2y=8~(I)} \atop {x-5y=3~ (II)}} \right. \\\\\\\\(II)~x-5y=3\to x=5y+3\\\\\\ Substitua~(II)~em~(I):\\\\ \\(I)~-3x-2y=8\to -3(5y+3)-2y=8\to -15y-9-2y=8\to \\\\ -15y-2y=8+9\to -17y=17~(-1)\to 17y=-17\to  y=- \frac{17}{17} \to\\\\ \boxed{ y=-1}\\\\\\ Substitua~(I)~em~(II):\\\\\\ (II)~x=5y+3\to x=5.(-1)+3\to x=-5+3\to \boxed{x=-2}\\\\\\\\ S=\{-2;-1\}

adrianesalvar: Obrigada !
LuanaSC8: Por nada :D
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