Question

Como que racionaliza isso ?

Answer 1

$\frac{3+ \sqrt{3} }{ \sqrt{12} } = \frac{3+ \sqrt{3} }{ \sqrt{12} } \frac{ \sqrt{12} }{12} = \\ \\ = \frac{3 \sqrt{12}+ \sqrt{3} \sqrt{12} }{12} = \\ \\ = \frac{3 \sqrt{12}+ \sqrt{3.12} }{12} = \\ \\ = \frac{3 \sqrt{3.2^2}+ \sqrt{36} }{12} = \\ \\ = \frac{3.2 \sqrt{3}+ 6 }{12} = \\ \\ \\ = \frac{6 \sqrt{3}+ 6 }{12} = \\ \\ = \frac{6(\sqrt{3}+ 1 )}{12} = \frac{ \sqrt{3} +1}{2} = \\ \\ \frac{ \sqrt{3} }{2} + \frac{1}{2}$

Answer 2

Oie, Td Bom?!

$= \frac{3 + \sqrt{3} }{ \sqrt{12} }$

$= \frac{3 + \sqrt{3} }{2 \sqrt{3} }$

$= \frac{3 + \sqrt{3} }{2 \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} }$

$= \frac{(3 + \sqrt{3} ) \sqrt{3} }{2 \sqrt{3} \sqrt{3} }$

$= \frac{3 \sqrt{3} + 3}{2 \times 3}$

$= \frac{3( \sqrt{3} + 1) }{6}$

$= \frac{ \sqrt{3} + 1 }{2}$

Att. Makaveli1996