Question

m+n=40 m×n= -800 Determine o valor de m e n.

Answer 1

x² -(m+n)x + m.n = 0

x² - 40x - 800 = 0

∆= 1600 +3200= 4800 => √∆= 40√3

x = -b±√∆/2a

x = 40±40√3/2

m = 40+40√3/2 = 20 +20√3. ✓

n = 40-40√3/2 = 20 -20√3. ✓