Question

Me ajudem por favor ​

Answer 1

Resposta:

$3 {x}^{2} + 9x = 0 \\ a = 3 \: \: b = 9 \: \: c = 0 \\ delta = {9}^{2} - 4.3.0 \\ delta = 81 - 0 \\ delta = 81 \\ x = \frac{ - 9 + - \sqrt{81} }{2. 3} = \frac{ - 9 + - 9}{6} \\ \\ x = \frac{ - 9 + 9}{6} = \frac{0}{6} = 0 \\ \\ x = \frac{ - 9 - 9}{6} = \frac{ - 18}{6} = - 3$

Alternativa A