Question

determine o 15° termo da P.A (256,128,64,32)​

Answer 1

Resposta:

A fórmula:   an = q^n-1, a razão é 1/2

an = 256 . (1/2)^15-1

an = 2^8 . (1/2)^14

an = $2^{8} . (1/2)^{14} \\\\2^{8} . (2^{-1} )^{14} \\\\\\2^{8} . (2)^{-14}\\\\2^{-6}$

an = 1/64

Explicação passo-a-passo: