Question

Por favor preciso de ajuda!
Com solução:

b8494c97a9d0e61e38167f68b4e3feb3.docx

Answer 1

Bom dia Rosana!

Solução das matrizes.

$A=\left[\begin{array}{ccc}1&2&0\\1&1&0\\-1&4&0\end{array}\right]$

$C=\left[\begin{array}{ccc}1&2&3\\1&1&-1\\1&1&1\end{array}\right]$


$\left[\begin{array}{ccc}1&2&0\\1&1&0\\-1&4&0\end{array}\right] \times \left[\begin{array}{c}1&1&1\end{array}\right]= \left[\begin{array}{ccc}1.1+2.1+0.1\\1.1+1.1+0.1\\-1.1+4.1+0.4\end{array}\right] = \left[\begin{array}{c}3&2&3\\\end{array}\right]$

$\left[\begin{array}{ccc}1&2&0\\1&1&0\\-1&4&0\end{array}\right] \times \left[\begin{array}{c}2&1&1\end{array}\right]= \left[\begin{array}{ccc}1.2+2.1+0.1\\1.2+1.1+0.1\\-1.2+4.1+0.1\end{array}\right] = \left[\begin{array}{c}4&3&2\\\end{array}\right]$


$\left[\begin{array}{ccc}1&2&0\\1&1&0\\-1&4&0\end{array}\right] \times \left[\begin{array}{c}3&-1&1\end{array}\right]= \left[\begin{array}{ccc}1.3+2.-1+0.1\\1.3+1.-1+0.1\\-1.3+4.-1+0.1\end{array}\right] = \left[\begin{array}{c}1&2&-7\\\end{array}\right]$

$Resposta:A\times B= \left[\begin{array} {ccc}3&4&1\\2&3&2\\3&2&-7\end{array}\right]$

2) N-P+M

$-1\times \left[\begin{array}{ccc}0&1&-1\\2&0&-1\\3&-2&0\end{array}\right] = \left[\begin{array}{ccc}0&-1&1\\-2&0&1\\-3&2&0\end{array}\right]$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] + \left[\begin{array}{ccc}0&1&-1\\2&0&-1\\3&-2&0\end{array}\right]+ \left[\begin{array}{ccc}1&2&3\\-1&0&-2\\4&-3&5\end{array}\right]=$

$\left[\begin{array}{ccc}2&3&2\\1&1&-3\\7&-5&6\end{array}\right]$

Resposta:C

3) N-2(M-P)

$P= 2\times \left[\begin{array}{ccc}0&-1&1\\-2&0&1\\-3&2&0\end{array}\right] = \left[\begin{array}{ccc}0&-2&2\\-4&0&2\\-6&4&0\end{array}\right]$

$M=-2\times \left[\begin{array}{ccc}1&2&3\\-1&0&-2\\4&-3&5\end{array}\right]= \left[\begin{array}{ccc}-2&-4&-6\\2&0&4\\-8&6&-10\end{array}\right]$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]+ \left[\begin{array}{ccc}-2&-4&-6\\2&0&4\\-8&6&-10\end{array}\right] + \left[\begin{array}{ccc}0&-2&2\\-4&0&2\\-6&4&0\end{array}\right] =$

$\left[\begin{array}{ccc}-1&-6&-4\\-2&1&6\\-14&10&-9\end{array}\right]$

Resposta B

Bom dia!
Bons estudos!