Question

$11^{2x^2-5x+2}=1$
$5^{x:2=125}$
$0,2^{x:1}= \sqrt{125}$

Answer 1

$11^{2x^2-5x+2}=1\\ \\ 11^{2x^2-5x+2}=11^0\\ \\ 2x^2-5x+2=0\\ \\ S=\{\frac{1}{2},2 \}$

$5^{x+2}=125\\ \\ 5^{x+2}=5^3\\ \\ x+2=3\\ \\ x=1$

$0,2^{x+1}=\sqrt{125}\\ \\ (5^{-1})^{x+1}=5^{\frac{3}{2}}\\ \\ -x-1=\frac{3}{2}\\ \\ -2x-2=3\\ \\ -2x=5\\ \\ x=-\frac{5}{2}$