Question

(2x² + 7x + 6) + (6x + 10) ?

Answer 1

2x² + 7x + 6 + 6x + 10
2x² + 13x + 16 = 0

Δ = b2 - 4.a.c 
Δ = 132 - 4 . 2 . 16 
Δ = 169 - 4. 2 . 16 
Δ = 41
Há 2 raízes reais.

x = -b +- √Δ / 2a

x = -13 +- √41 / 2a

x' = -13 + √41 / 4
x'' = -13 - √41 / 4