Question

6) Considere a equação 8x² + 2x – 3 = 0. A metade da diferença entre a maior e a menor raiz é: * a) 5/8 b) 1/8 c) 3/8 d) -5/8 e) -3/8

Answer 1

8x² + 2x - 3 = 0

(4x + 3)(2x - 1) = 0

x = $-\frac{3}{4}; \frac{1}{2}$

$\frac{(\frac{1}{2} - (-\frac{3}{4})}{2} = \frac{(\frac{1}{2} + \frac{3}{4})}{2} = \frac{\frac{4 + 6}{8}}{2} = \frac{\frac{10}{8}}{2} = \frac{\frac{5}{4}}{2} = \frac{5}{4}.\frac{1}{2} = \frac{5}{8}$