• Matéria: Matemática
  • Autor: eduardanauta
  • Perguntado 6 anos atrás

A resposta desse calculo

Anexos:

Respostas

respondido por: kresleylucas
0

C^{P}_{n}   = \frac{n!}{P!(n-P)!}\\ \\C^{P}_{n}   = \frac{12!}{2!(12-2)!}\\\\\\C^{P}_{n}   = \frac{12!}{2!.10!}\\\\\\C^{P}_{n}   = \frac{12.11.10!}{2.1.10!}\\\\\\C^{P}_{n}   = \frac{12.11}{2}\\\\\\C^{P}_{n}   = \frac{132}{2}\\\\

∴ A quantidade de maneiras é 66.

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