Question

Resolva o sistema de equações a seguir: x^2+y^2=13 x-y=1

Answer 1

x^2 + y^2 = 13
x-y=1

x-y=1 》-y=1-x 》-y=1-x (-1) 》
y= -1+ x


x^2 + y^2 = 13
x^2 + (-1+x)^2=13
x^2 + 1 - 2x + x^2=13
x^2 + x^2 - 2x + 1=13
2x^2 - 2x + 1 - 13=0
2x^2 - 2x - 12=0

(2x^2 - 2x - 12)/2

x^2 - x - 6=0

delta=5

1-5/2
1+5/2

x1=-2

x2=3

x-y=1
-2-y=1
-y=1+2
-y=3 (-1)
y=3

3-y=1
-y=-3+1
-y=-2 (-1)
y=2



x1=-2

x2=3

y1=3
y2=2