Question

1) Calcule (Preciso das resoluções das contas, vale 50 PONTOS galera) // a) (10+a)² b) (2+3m)² // c) (a + 5x)² // d) (7-m)² // e) 5a-3)² // f) (1-4y)² // g) (c+d).(c-d) // h) (7-x).(7+x) // i) (a+12). (a-12) // j) (4x-1). (4x+1)

Answer 1

Explicação passo-a-passo:

a)

(10 + a)² = 10² + 2.10.a + a²

(10 + a)² = 100 + 20a + a²

b)

(2 + 3m)² = 2² + 2.2.3m + (3m)²

(2 + 3m)² = 4 + 12m + 9m²

c)

(a + 5x)² = a² + 2.a.5x + (5x)²

(a + 5x)² = a² + 10ax + 25x²

d)

(7 - m)² = 7² - 2.7.m + m²

(7 - m)² = 49 - 14m + m²

e)

(5a - 3)² = (5a)² - 2.5a.3 + 3²

(5a - 3)² = 25a² - 30a + 9

f)

(1 - 4y)² = 1² - 2.1.4y + (4y)²

(1 - 4y)² = 1 - 8y + 16y²

g)

(c + d).(c - d) = c² - d²

h)

(7 - x).(7 + x) = 7² - x²

(7 - x).(7 + x) = 49 - x²

i)

(a + 12).(a - 12) = a² - 12²

(a + 12).(a - 12) = a² - 144

j)

(4x - 1).(4x + 1) = (4x)² - 1²

(4x - 1).(4x + 1) = 16x² - 1

Answer 2

Oie, Td Bom?!

a)

$= (10 + a) {}^{2}$

$= 10 {}^{2} + 2 \: . \: 10a + a {}^{2}$

$= 100 + 20a + a {}^{2}$

$= a {}^{2} + 20a + 100$

b)

$= (2 + 3m) {}^{2}$

$= 2 {}^{2} + 2 \: . \: 2 \: . \: 3m + (3m) {}^{2}$

$= 4 + 12m + 9m {}^{2}$

$= 9m {}^{2} + 12m + 4$

c)

$= (a + 5x) {}^{2}$

$= a {}^{2} + 2a \: . \: 5x + (5x) {}^{2}$

$= a {}^{2} + 10ax + 25x {}^{2}$

d)

$= (7 - m) {}^{2}$

$= 7 {}^{2} - 2 \: . \: 7m + m {}^{2}$

$= 49 - 14m + m {}^{2}$

$= m {}^{2} - 14m + 49$

e)

$= (5a - 3) {}^{2}$

$= (5a) {}^{2} - 2 \: . \: 5a \: . \: 3 + 3 {}^{2}$

$= 25a {}^{2} - 30a + 9$

f)

$= ( 1 - 4 y){}^{2}$

$= 1 {}^{2} - 2 \: . \: 1 \: . \: 4y + (4y) {}^{2}$

$= 1 - 8y + 16y {}^{2}$

$= 16y {}^{2} - 8y + 1$

g)

$= (c + d) \: . \: (c - d)$

$= c {}^{2} - d {}^{2}$

h)

$= (7 - x) \: . \: (7 + x)$

$= 7 {}^{2} - x {}^{2}$

$= 49 - x {}^{2}$

i)

$= (a + 12) \: . \: (a - 12)$

$= a {}^{2} - 12 {}^{2}$

$= a {}^{2} - 144$

j)

$= (4x - 1) \: . \: (4x + 1)$

$= (4x) {}^{2} - 1 {}^{2}$

$= 16x {}^{2} - 1$

Att. Makaveli1996