Question

MATEMÁTICA
5 PONTOS!!​

Answer 1

Resposta:

$\sf \sin{45^\circ} = \dfrac{\mbox {\sf Cateto Op0sto }}{Hipotenusa}$

$\sf \dfrac{\sqrt{2} }{2} = \dfrac{10}{BC}$

$\sf \sqrt{2}\;BC = 2 \times 10$

$\sf \sqrt{2} \;BC = 20$

$\sf BC = \dfrac{20}{\sqrt{2} } \quad \gets \mbox {\sf deve racionalizar o denominador.}$

$\sf BC = \dfrac{20}{\sqrt{2} } \times \dfrac{\sqrt{2} }{\sqrt{2} } = \dfrac{20 \sqrt{2} }{\sqrt{2^2} } = \dfrac{20 \sqrt{2} }{2 } = 10\sqrt{2} = 10 \times 1,41 = \boxed{\boxed {\sf 14,10 \, cm}}$

Explicação passo-a-passo:

Answer 2

Resposta:

saaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaabio

Explicação passo-a-passo: