Question

x²-52x-32=0
me ajudem pfv
e um exercício para resolver em delta​

Answer 1

Explicação passo-a-passo:

$\sf x^2-52x-32=0$

$\sf \Delta=(-52)^2-4\cdot1\cdot(-32)$

$\sf \Delta=2704+128$

$\sf \Delta=2832$

$\sf x=\dfrac{-(-52)\pm\sqrt{2832}}{2\cdot1}=\dfrac{52\pm4\sqrt{177}}{2}$

$\sf x'=\dfrac{52+4\sqrt{177}}{2}~\Rightarrow~\red{x'=26+2\sqrt{177}}$

$\sf x"=\dfrac{52-4\sqrt{177}}{2}~\Rightarrow~\red{x"=26-2\sqrt{177}}$