Question

e P(x)=x³-5x²+8x-4 e Q(x)=x³-x²-8x+10, então P(2)/Q(2) é igual a:?

Answer 1

$P(x) = x^3-5x^2+8x-4 \\ \\ P(2)=2^3-5.2^2+8.2-4 \\ \\ P(2)=8-5.4+16-4 \\ \\ P(2)=8-20+16-4 \\ \\ P(2)= 24-24=0 \\ \\ \\ Q(x)=x^3-x^2-8x+10 \\ \\ Q(2)=2^3-2^2-8.2+10 \\ \\ Q(2)=8-4-16+10 \\ \\ Q(2)=18-20 \\ \\ Q(2)=-2 \\ \\ \\ \frac{P(2)}{Q(2)} = \frac{0}{-2} =0$