Question

Utilizando o método que preferir resolva as equações abaixo

Answer 1

Oie, td bom?

$a) x^2 - 10x + 9 = 0\\\\a + b = -10\\ab = 9\\\\Fatore:\\- 1, -9 => -1 -9 = -10\\-3, -3 => -3 -3 = -6\\\\a = -9\\b = -1\\\\(x - 9)(x - 1) \\\\Para - localizar solucoes de equacao, solucione (x - 9) = 0; (x -1) = 0\\\\x = 9\\x = 1$

$b) 2x^2 - 9x +4 = 0\\a + b = -9\\ab = 2 x4 = 8\\\\Fatore:\\-1, -8 => -1 -8 = -9\\-2, -4 => -2 -4 = -6\\\\a = -8\\b = -1\\\\(2x^2 - 8x) + (-x +4) => 2x (x -4) + (x -4)\\\\(x -4) (2x - 1)\\\\x -4 = 0; 2x -1 = 0\\\\x = -4\\\\x = \frac{1}{2}$

$c) x^2 + 8x +16 = 0\\a +b= 8\\ab = 16\\\\Fatore:\\1, 16 => 1 + 16 = 17\\2, 8 => 2 + 8 = 10\\4, 4 => 4 + 4 = 8\\\\a = 4\\b = 4\\\\(x +4)^2\\\\x + 4 = 0; x = -4\\\\\\x = -4$

Espero ter ajudado...tchau e bons estudos!!

Answer 2

Resposta:

Oie, td bom?