Question

transforme as frações improprias em números mistos :
a)9\5
b)8\3
c)15\13
d)12\5
e)9\4
f)18\11
g)10\4
h)19\3
i)80\33
j)142\67

Answer 1

Explicação passo-a-passo:

a) $\sf \dfrac{9}{5}=\dfrac{5+4}{5}=\dfrac{5}{5}+\dfrac{4}{5}=\red{1~\dfrac{4}{5}}$

b) $\sf \dfrac{8}{3}=\dfrac{6+2}{3}=\dfrac{6}{3}+\dfrac{2}{3}=\red{2~\dfrac{2}{3}}$

c) $\sf \dfrac{15}{13}=\dfrac{13+2}{13}=\dfrac{13}{13}+\dfrac{2}{13}=\red{1~\dfrac{2}{13}}$

d) $\sf \dfrac{12}{5}=\dfrac{10+2}{5}=\dfrac{10}{5}+\dfrac{2}{5}=\red{2~\dfrac{2}{5}}$

e) $\sf \dfrac{9}{4}=\dfrac{8+1}{4}=\dfrac{8}{4}+\dfrac{1}{4}=\red{2~\dfrac{1}{4}}$

f) $\sf \dfrac{18}{11}=\dfrac{11+7}{11}=\dfrac{11}{11}+\dfrac{7}{11}=\red{1~\dfrac{7}{11}}$

g) $\sf \dfrac{10}{4}=\dfrac{8+2}{4}=\dfrac{8}{4}+\dfrac{2}{4}=\red{2~\dfrac{2}{4}}$

h) $\sf \dfrac{19}{3}=\dfrac{18+1}{3}=\dfrac{18}{3}+\dfrac{1}{3}=\red{6~\dfrac{1}{3}}$

i) $\sf \dfrac{80}{33}=\dfrac{66+14}{33}=\dfrac{66}{33}+\dfrac{14}{33}=\red{2~\dfrac{14}{33}}$

j) $\sf \dfrac{142}{67}=\dfrac{134+8}{67}=\dfrac{134}{67}+\dfrac{8}{67}=\red{2~\dfrac{8}{67}}$