Question

Alguém me ajudaaa!!!!!!!!!!​

Answer 1

Resposta:

a)

$a {}^{6} \times a {}^{4} = a {}^{6 + 4} = a {}^{10}$

b)

$\frac{ {5}^{7} }{ {5}^{2} } = {5}^{7 - 2} = {5}^{5}$

c)

$( \frac{3}{5} ) {}^{ - 3} \times ( \frac{5}{3} ) {}^{4} \div ( \frac{5}{3} ) { }^{ - 4} \\ ( \frac{5}{3} ) {}^{3} \times ( \frac{5}{3} ) {}^{4} \div ( \frac{5}{3} ) {}^{ - 4} \\ \frac{ (\frac{5}{3}) {}^{3 + 4} }{( \frac{5}{3} ) {}^{ - 4} } = \frac{( \frac{5}{3} ) {}^{7} }{( \frac{5}{3}) {}^{ - 4} } = \\ (\frac{5}{3} ) {}^{7 - ( - 4)} = (\frac{5}{3} ) {}^{7 + 4} = ( \frac{5}{3} ) {}^{11}$

d)

$( \frac{ {3}^{4} \times {3}^{5} \times {3}^{ - 2} }{ {3}^{9} \div {3}^{2} } ) {}^{ \frac{1}{2} } = \\ \\ ( \frac{3 {}^{4 + 5 + ( - 2)} }{ {3}^{9 - 2} } ) {}^{ \frac{1}{2} } = \\ \\ ( \frac{ {3}^{9 - 2} }{ {3}^{7} } ) {}^{ \frac{1}{2} } = \\ \\ ( \frac{ {3}^{7} }{ {3}^{7} } ) {}^{ \frac{1}{2} } = ( {3}^{7 - 7} ) {}^{ \frac{1}{2} } = \\ \\ ( {3}^{0} ) {}^{ \frac{1}{2} } = {3}^{0 \times \frac{1}{2} } = {3}^{0}$

Bons Estudos!