Question

$\lim_{x \to \4} \frac{3 x^{2}-17x+20 }{4 x^{2} -25x+36}$

Answer 1

$\lim_{x \to 4} \frac{3x^2-17x+20}{4x^2-25x+36} = \lim_{x \to } \frac{(3 x-5) (x-4)}{(4 x-9) (x-4)}= \lim_{x \to 4} \frac{3x-5}{4x-9}=\frac{3.4-5}{4.4-9}=\frac{7}{7}=1$