Question

calcule a expressão {[(-8+2-3):(3)³+5.(-3)]-32} 

Answer 1

$\left{\left[(-8+2-3)\div(3)^3+5\cdot(-3)\right]-32\right}=\\\\\left{\left[(-9)\div(3)^3-15\right]-32\right}=\\\\\left{\left[\frac{-9}{27}-15\right]-32\right}=\\\\\left{\left[\frac{-1}{3/15}-\frac{15}{1/3}\right]-32\right}=\\\\\frac{-15-45}{3}-32=\\\\\frac{-60}{3}-32=\\\\-20-32=\\\\\boxed{-52}$