Question

converta os valores para( kl) a)4532L KL b)0,48 hL KL c)32daL KL d)58 932 dL KL e)53L KL f )680L kL

Answer 1

Explicação passo-a-passo:

$a)4532L= 4532\frac{k}{10^3} L =4532.10^-^3kL=4,532kL\\\\b)0,48 hL= 0,48.(10^2).\frac{k}{10^3} L=0,48.10^2.10^-^3 kL=0,48.10^-^1k L=0,048kL \\\\c)32daL=32.(10^1).\frac{k}{10^3} L=32.10^1.10^-^3 kL=32.10^-^2k L=0,32kL \\\\d)58 932 dL= 58 932.(10^-^1).\frac{k}{10^3} L=58 932.10^-^1.10^-^3 kL=58 932.10^-^4k L=5,8932kL \\\\ \\e)53L= 53\frac{k}{10^3} L =53.10^-^3kL=0,053kL$

$f)680L=680\frac{k}{10^3}L= 680.10^-^3kL=0,68kL$