• Matéria: Matemática
  • Autor: Ellenmesquita19
  • Perguntado 5 anos atrás

Quais são os valores de xey
(x + y = 136
x/y=5/12

Respostas

respondido por: pedroosilvah
3

\left \{ {{x + y = 136} \atop {\frac{x}{y} = \frac{5}{12}  }} \right.\\ \\\left \{ {{x = 136 - y} \atop {\frac{x}{y} = \frac{5}{12}  }} \right.\\ \\\left \{ {{x = 136 - y} \atop {\frac{136 - y}{y} = \frac{5}{12}  }} \right.\\\\\left \{ {{x = 136 - y} \atop {(136 - y)*12 = 5y}} \right.\\\\\left \{ {{x = 136 - y} \atop {1632- 12y= 5y}} \right.\\\\\left \{ {{x = 136 - y} \atop {1632- 12y - 5y= 0}} \right.\\\left \{ {{x = 136 - y} \atop {-17y= -1632}} \right.\\\left \{ {{x = 136 - y} \atop {y = 96}

\left \{ {{x = 136 - 96} \atop {y = 96} \right \\\\\left \{ {{x = 40} \atop {y = 96}} \right.

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