Question

me explique?
(2x-1)² + 3(x+1)=7

Answer 1

$(2x-1)^2+3(x+1)=7\\4x^2-4x+1+3x+3=7\\4x^2-x+4=7\\4x^2-x-3=0$


$4x^2-x-3=0\\\Delta=(-1)^2-4-4.(-3)\\\Delta=1+48\\\Delta=49$

$x= \frac{-b\pm \sqrt{\Delta} }{2a}$

$x= \frac{1\pm7}{8}$

$\boxed{x'= \frac{1-7}{8} ~\to~ \frac{-6^{\div2}}{8^{\div2}} ~\to~- \frac{3}{4} }$

$\boxed{x''= \frac{1+7}{8} ~\to~ \frac{8}{8} ~\to~1}$