Question

Encontre $\lim_{n \to \infty} \frac{x^{2} (2+sen^{2} x)}{x+100}$

Answer 1

Resposta:

OLÁ

VAMOS A SUA PERGUNTA:⇒⇒

$\sf \lim_{n \to \infty} \dfrac{x^2(2+sen^2~x)}{x+100}$

$\sf \sf \lim_{n \to \infty} \left(\dfrac {x^2(2+sin^2~(x))}{x+100}\right)$

$\sf \sf= \lim_{n \to \infty} \left(\dfrac {x(sin^2~(x)+2)}{1+\dfrac{100}{x} }\right)$

$\sf =\dfrac{ \lim_{n \to \infty} (x(sin^2(x)+2)) }{ \lim_{n \to \infty} \left(1+\dfrac{100}{x}\right) }$

$\sf \lim_{n \to \infty} \left(x(\left sin^2(x)+2)\right)= \infty$

$\sf \lim_{n \to \infty} \left(1+\dfrac{100}{x}\right)=1$

$\sf =\dfrac{\infty}{1}$

$\sf \dfrac{\infty}{c}=\infty$

$\boxed{\bold{\displaystyle{\clubsuit\ \spadesuit\ \maltese\ \sf \green{=\infty} }}}\ \checkmark$← RESPOSTA.

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