Question

qual o valor do limite ??!

Answer 1

Explicação passo-a-passo:

$\sf \lim_{x~\to~0}~\dfrac{x^3+3x}{2x}$

$\sf =\lim_{x~\to~0}~\dfrac{x\cdot(x^2+3)}{x\cdot2}$

$\sf =\lim_{x~\to~0}~\dfrac{x^2+3}{2}$

$\sf =\dfrac{0^2+3}{2}$

$\sf =\dfrac{3}{2}$

$\sf =1,5$

Answer 2

Oie, Td Bom?!

$= lim_{x⟶0}( \frac{x {}^{3} + 3x}{2x} )$

$= lim_{x⟶0}( \frac{x \: . \: (x {}^{2} + 3) }{2x} )$

$= lim_{x⟶0}( \frac{x {}^{2} + 3}{2} )$

$= \frac{ lim_{x⟶0}(x {}^{2} + 3) }{ lim_{x⟶0}(2) }$

$= \frac{ lim_{x⟶0}(x {}^{2} ) + lim_{x⟶0}(3) }{2}$

$= \frac{( lim_{x⟶0}(x) ) {}^{2} +3 }{2}$

$= \frac{0 {}^{2} + 3}{2}$

$= \frac{0 + 3}{2}$

$= \frac{3}{2}$

$= 1,5$

Att. Makaveli1996