Question

1) DETERMINE O VALOR DE “X” NO TRIÂNGULO A SEGUIR:
13
B
12
RESPOSTA:​

Answer 1

$\sf x^2+12^2=13^2$

$\sf x^2+144=169$

$\sf x^2=169-144$

$\sf x^2=25$

$\sf x=\sqrt{25}$

$\boxed{\boxed{\sf x=5}}$