Question

1°Determine o zero da função :
A) f(x)=-6x²+2x+4

Answer 1

Resposta:

1 e -⅔

Explicação passo-a-passo:

∆=b²-4ac

∆=2²-4(-6)(4)

∆=4+24(4)

∆=4+96

∆=100

X=(-b+/-√∆)/2a

X1=(-2-√100)/-12

X1=(-2-10)/-12

X1=-12/-12

X1=1

X2=(-2+√100)/-12

X2=(-2+10)/-12

X2=8/-12

X2=-2/3

Answer 2

Oie, Td Bom?!

$f(x) = - 6x {}^{2} + 2x + 4$

$0 = - 6x {}^{2} + 2x + 4$

$- 6x {}^{2} + 2x + 4 = 0$

$3x {}^{2} - x - 2 = 0$

$3x {}^{2} + 2x - 3x - 2 = 0$

$(3x + 2) \: . \: (x - 1) = 0$

• $3x + 2 = 0⇒3x = - 2⇒x = - \frac{2}{3}$

• $x - 1 = 0⇒x = 1$

$S = \left \{ - \frac{2}{3} \: ,\: 1\right \}$

Att. Makaveli1996