Question

Me ayudan?x√(x-1 )dx

Answer 1

Resposta:

∫ x√(x-1 ) dx

Substitua u=x-1  ==>du=dx

u=x-1 ==>x=u+1

∫ (u+1)*√u du

∫ u√u du  + ∫ √u du

∫ u^(3/2) du  + ∫ √u du

=[ u^(3/2+1)  ]/(3/2+1) + [u^(1/2+1)]/(1/2+1)  +c

=(2/5)* u^(5/2)  + (2/3) * u^(3/2) + c

Como u = x-1  

=(2/5)* (x-1)^(5/2)  + (2/3) * (x-1)^(3/2) + c