Question

Integral ∫(x²+1)⁴2xdx

Answer 1

Resposta:

[(x²+1)^5]/5 + c

Explicação passo-a-passo:

∫(x²+1)⁴2xdx

x²+1 = v

2xdx = dv

dx = dv/2x

∫(x²+1)⁴2xdx

∫(v)⁴2xdv/2x, cancela 2x.

∫(v)⁴dv

v^(4+1)/(4+1) =

v^5/5

[(x²+1)^5]/5 + c