Question

me ajudem por favor​

Answer 1

a)

$( { \frac{1}{8} })^{ - 2} = {8}^{2} = 64 \\ \\( { \frac{1}{2} })^{4} = \frac{ {1}^{4} }{ {2}^{4} } = \frac{1}{16} \\ \\ 64 \times \frac{1}{16} = \frac{64}{16} = 4$

b)

$({ \frac{1}{4} })^{0} = 1 \\ \\ ( { \frac{1}{2} })^{3} = \frac{ {1}^{3} }{ {2}^{3} } = \frac{1}{8} \\ \\ \frac{1}{3} \times \frac{1}{8} = \frac{1}{24} \\ \\ 1 - \frac{1}{24} = \frac{23}{24}$