Respostas
Explicação passo-a-passo:
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a)
= (2x {}^{3} - 5) {}^{2}=(2x3−5)2
= (2x {}^{3} ) {}^{2} - 2 \: . \: 2x {}^{3} \: . \: 5 + 5 {}^{2}=(2x3)2−2.2x3.5+52
= 4x {}^{6} - 20x {}^{3} + 25=4x6−20x3+25
b)
= (8x - 7a) {}^{2}=(8x−7a)2
= (8x) {}^{2} - 2 \: .\: 8x \: . \: 7a + (7a) {}^{2}=(8x)2−2.8x.7a+(7a)2
= 64x {}^{2} - 112ax + 49a {}^{2}=64x2−112ax+49a2
c)
= (6 - a {}^{3} ) {}^{2}=(6−a3)2
= 6 {}^{2} - 2 \: . \: 6a {}^{3} + (a {}^{3} ) {}^{2}=62−2.6a3+(a3)2
= 36 - 12a {}^{3} + a {}^{6}=36−12a3+a6
= a {}^{6} - 12a {}^{3} + 36=a6−12a3+36
d)
= (3a {}^{2} + 1) {}^{2}=(3a2+1)2
= (3a {}^{2} ) {}^{2} + 2 \: . \: 3a {}^{2} \: . \: 1 + 1 {}^{2}=(3a2)2+2.3a2.1+12
= 9a {}^{4} + 6a {}^{2} + 1=9a4+6a2+1
e)
= (10p + 3q) {}^{2}=(10p+3q)2
= (10p) {}^{2} + 2 \: . \: 10p \: . \: 3q + (3q) {}^{2}=(10p)2+2.10p.3q+(3q)2
= 100p {}^{2} + 60pq + 9q {}^{2}=100p2+60pq+9q2
f)
= (1 + pq) {}^{2}=(1+pq)2
= 1 {}^{2} + 2 \: . \: 1pq + (pq) {}^{2}=12+2.1pq+(pq)2
= 1 + 2pq + p {}^{2} q {}^{2}=1+2pq+p2q2
g)
= (x + \frac{1}{3} ) {}^{2}=(x+31)2
= x {}^{2} + 2x \: . \: \frac{1}{3} + ( \frac{1}{3} ) {}^{2}=x2+2x.31+(31)2
= x {}^{2} + \frac{2}{3} x + \frac{1}{9}=x2+32x+91
h)
= (b + \frac{3}{4} ) {}^{2}=(b+43)2
= b {}^{2} + 2b \: . \: \frac{3}{4} + ( \frac{3}{4} ) {}^{2}=b2+2b.43+(43)2
= b {}^{2} + \frac{3}{2} b + \frac{9}{16}=b2+
Resposta:
Alternativa "B"
Explicação passo-a-passo:
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