Question

URGENTE!!


1- Sendo f(x) = 2x²-5x+3 , calcule:

a) f(1) =

b) f(-2) =

c) f(2)=

d) x de modo que f(x) = 0​

2- Sendo f(x) = -3x² + 5x - 3, calcule:
a) f (-1)=

b) f(2)=

c) f(3)=

d) x de modo que f (x)= 0

Answer 1

Resposta:

1)a)f(1)=2x²-5x+3

f(1)=2.(1)^2-5.1+3

f(1)=2.1-5.1+3

f(1)=2-5+3

f(1)=0

B)f(-2)=2x²-5x+3

f(-2)=2.(-2)^2-5.(-2)+3

f(-2)=2.4+10+3

f(-2)=8+13

f(-2)=21.

C)f(2)=2x²-5x+3

f(2)=2.2^2-5.2+3

f(2)=2.4-10+3

f(2)=8-10+3

f(2)=1

D)f(0)=2x²-5x+3

f(0)=2.0^2-5.0+3

f(0)=2.0-5.0+3

f(0)=0-0+3

f(0)=3

2)a) f (-1)=-3x² + 5x - 3

f(-1)= -3.(-1)^2+5.(-1)-3

f(-1)= -3.1-5-3

f(-1)= -3-5-3

f(-1)= -11

b) f(2)=-3x² + 5x - 3

f(2)=-3.2^2+5.2-3

f(2)=-3.4+5.2-3

f(2)=-12+10-3

f(2)=-5

c) f(3)=-3x² + 5x - 3

f(3)=-3.3^2+5.3-3

f(3)=-3.9+5.3-3

f(3)=-27+15-3

f(3)=-15

d) f(0)=-3x² + 5x - 3

f(0)=-3.0^2+5.0-3

f(0)=-3.0+5.0-3

f(0)=-0+0-3

f(0)= -3