Question

Sistema lineares

2x - 3y = 3
3x + 2y = 37

Resolva pelo método da substituição

Answer 1

$\begin{cases}2x - 3y = 3\\3x + 2y = 37\end{cases}\\\\\\\\ 2x - 3y = 3\to~~ 2x=3y+3\to~~ x= \dfrac{3y+3}{2} \\\\\\3x + 2y = 37\to~~3\left(\dfrac{3y+3}{2} \right) + 2y = 37\to~~ \dfrac{9y+9}{2} +2y=37\to\\mmc=2\\9y+9+4y=74\to~~ 9y+4y=74-9\to~~13y=65\to~~ y= \dfrac{65}{13} \to\\ \boxed{y=5}\\\\\\x= \dfrac{3y+3}{2}\to~~x= \dfrac{3.5+3}{2}\to~~x= \dfrac{15+3}{2}\to~~x= \dfrac{18}{2}\to~~ \boxed{x=9}\\\\\\\\\\ \large\boxed{\boxed{S=\{9~;~5\}}}$