Question

4) (3,0pm) Dada a função f(x)= 8x+15, calcule:
a) f(3)-f(0)=

b) f(2)+ f(3) =
c) f(x)=0=

d) f(x)=11=​

Answer 1

$f(x) = 8x + 15$

a)

$f(3) = 8(3) + 15 = 24 + 15 = 39\\f(0) = 8(0) + 15 = 15\\f(3) - f(0) = 39 - 15 = 24$

b)

$f(2) = 8(2) + 15 = 31\\f(3) = 39\\f(2) + f(3) = 70$

c)

$f(0) = 15$

d)

$f(x) = 8x + 15 = 11\\8x + 15 = 11\\8x = 11 - 15\\8x = -4\\x = -\frac{4}{8}\\x = -\frac{1}{2}$