Question

encontre as raizes das seguintes equacoes
-2x²+4x+6=0

Answer 1

-2x²+4x+6=0
∆=b²-4ac
∆=4²-4.(-2).6
∆=16+48
∆=64
x=-b±√∆/2a
x=-4-8/2.(-2)
x=-12/-4
x=3
x=-4+8/2.(-2)
x=4/-4
x=-1
S={(-1, 3)}