Question

determine as raizes das equaçoes do 2°grau
A)x²-12x+20=0

B)x²-6x+8=0

C)x²-3X+2=0

D)x²-4x-5=0

E)6x²+x-1=0

F)3x²-7x+2=0
preciso urgente tambem

Answer 1

Explicação passo-a-passo:

a) x^2 - 12x + 20 = 0

x= -(-12)+-\(-12)2-4*1*20/2*1

x=12+-\144-80/2

x=12+-\64/2

x=12+-8/2

x'=12+8/2=20/2=10

x"=12-8/2=4/2=2

b)x^2-6x+8=0

x= -(-6)+-\(-6)^2-4*1*8/2*1

x=6+-\36-32/2

x=6+-\4/2

x=6+-2/2

x'=6+2/2=8/2=4

x"=6-2/2=4/2=2

c)x^2-3x+2=0

x= -(-3)+-\(-3)^2-4*1*2/2*1

x=3+-\9-8/2

x=3+-\1/2

x=3+-1/2

x'=3+1/2=4/2=2

x"=3-1/2=2/2=1

d)x^2-4x-5=0

x= -(-4)+-\(-4)^2-4*1*(-5)/2*1

x=4+-\16+20/2

x=4+-\36/2

x=4+-6/2

x'=4+6/2=10/2=5

x"=4-6/2=-2/2=-1

e)6x^2+x-1=0

x= -1+-\1^2-4*6*(-1)/2*6

x= -1+-\1+24/12

x= -1+-\25/12

x= -1+-5/12

x'= -1+5/12=4/12=1/3

x"= -1-5/12=-6/12=-1/2

f)3x^2-7x+2=0

x= -(-7)+-\(-7)^2-4*3*2/2*3

x=7+-\49-24/6

x=7+-\25/6

x=7+-5/6

x'=7+5/6=12/6=2

x"=7-5/6=2/6=1/3