Question

u; Fe = 56 u; C = 12 u; N = 14 u; Ca
= 40 u; O = 16 u; S = 32 u)
imico
K4Fe(CN)6; CaCO3; HNO3; K2504
50 U,
te.
a)298,4 g/mol; 100 g/mol; 63 g/mol
e 174,2 g/mol
b)368,4 g/mol; 100 g/mol; 98 g/mol
e 174,2 g/mol
c)172,2 g/mol; 100 g/mol; 63 g/mol e
368,4 g/mol
d)308,4 g/mol; 63 g/mol; 98 g/moi e
174,2 g/mol
e) 368,4 g/mol; 100 g/mol; 63 g/mol
e 174,2 g/Molly​

Answer 1

Resposta:e) 368,4 g/mol; 100 g/mol; 63 g/mol

e 174,2 g/Molly​

Explicação:

K4Fe(CN)6-->39.4+56.1+12.6+14.6-->156+56+72+84-->368 g/mol

CaCO3-->40.1+12.1+16.3-->40+12+48-->100 g/mol

HNO3-->1.1+14.1+16.3-->1+14+48-->63 g/mol

K2S04 -->39.2+32.1+16.4-->78+32+64-->174 g/mol