Question

*100 PONTOS!*
No plano abaixo faça o gráfico da função
f(x) = sen x com x ∈ [−2π,2π].

Answer 1

x f(x)=sen(x)

-2π f(-2π)=sen(-2π)=0

-3π/2 f(-3π/2)=sen(3π/2)= -1

-π f(-π)=sen(-π)=0

-π/2 f(-π/2)=sen(-π/2)=1

0 f(0)=sen(0)=0

π/2 f(π/2)=sen(π/2)=1

π f(π)=sen(π)=0

3π/2 f(3π/2)=sen(3π/2)= -1

2π f(2π)=sen(2π)=0

Answer 2

x f(x)=sen(x)

-2π f(-2π)=sen(-2π)=0

-3π/2 f(-3π/2)=sen(3π/2)= -1

-π f(-π)=sen(-π)=0

-π/2 f(-π/2)=sen(-π/2)=1

0 f(0)=sen(0)=0

π/2 f(π/2)=sen(π/2)=1

π f(π)=sen(π)=0

3π/2 f(3π/2)=sen(3π/2)= -1

2π f(2π)=sen(2π)=0