Question

calcule a integral:
∫(2x-3x^2) dx

Answer 1

Resposta:

∫(2x-3x^2) dx

=2x²/2 -3 *x²⁺¹/(2+1) + c

=x² -3*x³/3+ c

=x² - x³+ c

= -x³ +x²+c