Question

x quadrado-5x=-6
como resolver

Answer 1

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$\boxed{\begin{array}{l}\sf x^2-5x=-6\\\sf x^2-5x+6=0\\\sf\Delta=b^2-4ac\\\sf\Delta=(-5)^2-4\cdot1\cdot6\\\sf\Delta=25-24\\\sf\Delta=1\\\sf x=\dfrac{-b\pm\sqrt{\Delta}}{2a}\\\sf x=\dfrac{-(-5)\pm\sqrt{1}}{2}\\\sf x=\dfrac{5\pm1}{2}\begin{cases}\sf x_1=\dfrac{5+1}{2}=\dfrac{6}{2}=3\\\sf x_2=\dfrac{5-1}{2}=\dfrac{4}{2}=2\end{cases}\\\sf \huge S=\bigg\{2,3\bigg\}\end{array}}$

Answer 2

x²-5x+6=0

Delta= (-5)²-4.1.6 x¹= 5+1÷2= ""3""

Delta= 25-24= 1

x¹ e x²= -(-5) +/- 1÷2.1

x²=5-1÷2= ""2""