Question

a= x² -4x +3 b= -2x³ +x² c= -2x +4 então quanto é a×b×c?


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Answer 1

Oie, Tudo Bom?

$= a \: . \: b \: . \: c$

$= (x {}^{2} - 4x + 3) \: . \: ( - 2x {}^{3} + x {}^{2} ) \: . \: ( - 2x + 4)$

$= x {}^{2} \: . \: ( - 2x {}^{3} + x {}^{2} ) - 4x \: . \: ( - 2x {}^{3} + x {}^{2} ) + 3( - 2x {}^{3} + x {}^{2} ) \: . \: ( - 2x + 4)$

$= ( - 2x {}^{5} + x {}^{4} + 8x {}^{4} - 4x {}^{3} - 6x {}^{3} + 3x {}^{2} ) \: . \: ( - 2x + 4)$

$= ( - 2x {}^{5} + 9x {}^{4} - 10x {}^{3} + 3x {}^{2} ) \: . \: ( - 2x + 4)$

$= - 2x {}^{5} \: . \: ( - 2x) - 2x {}^{5} \: . \: 4 - 9x {}^{4} \: . \: 2x + 9x {}^{4} \: . \: 4 - 10x {}^{3} \: . \: ( - 2x) - 10x {}^{3} \: . \: 4 - 3x {}^{2} \: . \: 2x + 3x {}^{2} \: . \: 4$

$= 4x {}^{6} - 8x {}^{5} - 18x {}^{5} + 36x {}^{4} + 20x {}^{4} - 40x {}^{3} - 6x {}^{3} + 12x {}^{2}$

$\boxed{ = 4x {}^{6} - 26x {}^{5} + 56x {}^{4} - 46x {}^{3} + 12x {}^{2} }$

Att. Makaveli1996