Question

combinações simples 6,3

Answer 1

Boa tarde Alex!

Solução!

$C_{n,p} = \dfrac{n!}{p!(n-p)!}$

Substituindo na formula.

$n=6\\\\ p=3$

$C_{6,3} = \dfrac{6!}{3!(6-3)!}$


$C_{6,3} = \dfrac{6!}{3!(3)!}$


$C_{6,3} = \dfrac{6\times5\times4\times3!}{3!3!}$


$C_{6,3} = \dfrac{6\times5\times4}{3\times2\times1}$


$C_{6,3} = \dfrac{120}{6}$


$C_{6,3} = 20$

Boa tarde!
Bons estudos!