Question

Sendo J = {32÷[(9-3)÷2+5]+3}×2 e R = {[(42÷6+1)÷2+1]×3-7}÷4×3+1,qual é o valor de J÷R?

Me ajudem por favor.

Answer 1

Resposta:

14 : 7 = 2

Explicação passo-a-passo:

J = {32÷[(9-3)÷2+5]+3}×2

J = {32÷[6÷2+5]+3}×2

J = {32÷[3+5]+3}×2

J = {32÷8+3}×2

J = {4+3}×2

J = 7×2

J = 14

R = {[(42÷6+1)÷2+1]×3-7}÷4×3+1

R = {[(7+1)÷2+1]×3-7}÷4×3+1

R = {[8÷2+1]×3-7}÷4×3+1

R = {[4+1]×3-7}÷4×3+1

R = {5×3-7}÷4×3+1

R = {15-7}÷4×3+1

R = 8÷4×3+1

R = 2×3+1

R = 6+1

R = 7

14 : 7 = 2

Answer 2

J = {32 ÷ [(9 - 3) ÷ 2 + 5] + 3} × 2

J = {32 ÷ [6 ÷ 2 + 5] + 3} × 2

J = {32 ÷ [3 + 5] + 3} × 2

J = {32 ÷ 8 + 3} × 2

J = {4 + 3} × 2

J = 7 × 2

J = 14

R = {[(42 ÷ 6 + 1) ÷ 2 + 1] × 3 - 7} ÷ 4 × 3 + 1

R = {[(7 + 1) ÷ 2 + 1] × 3 - 7} ÷ 4 × 3 + 1

R = {[8 ÷ 2 + 1] × 3 - 7} ÷ 4 × 3 + 1

R = {[4 + 1] × 3 - 7} ÷ 4 × 3 + 1

R = {5 × 3 - 7} ÷ 4 × 3 + 1

R = {15 - 7} ÷ 4 × 3 + 1

R = 8 ÷ 4 × 3 + 1

R = 2 × 3 + 1

R = 6 + 1

R = 7

J ÷ R = 14 ÷ 7

J ÷ R = 2