Question

considere que x2 y2 pode-se afirmar que a expressao em z equivale a:

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Answer 1

Resposta:

$z = \frac{1}{(x + y)}$

Explicação passo-a-passo:

$z = \frac{(x + y)^{2} - 4xy }{ {x}^{2} - {y}^{2} }$

$z = \frac{x(x + y) + y(x + y) - 4xy}{ {x}^{2} - {y}^{2} }$

$z = \frac{ {x}^{2} + xy + xy + {y}^{2} - 4xy }{(x + y) \times (x - y)}$

$z = \frac{ {x}^{2} + 2xy - 4xy + {y}^{2} }{(x + y) \times (x - y)}$

$z = \frac{ {x}^{2} - 2xy + {y}^{2} }{(x + y) \times (x - y)}$

$z = \frac{(x - y)^{2} }{(x + y) \times (x - y)}$

$z = \frac{(x - y) \times (x - y)}{(x - y) \times (x + y)}$

$z = \frac{(x - y)}{(x - y)} \times \frac{1}{(x + y)}$

$z = \frac{1}{x + y}$