Question

Determine a massa (em g) correspondente a:
2 mols de NaOH
1,5 mol de Al2O3
½ mol de HNO3
10 mols de Ca(OH)2

Answer 1

NaOH

Na = 23 g/mol x 1 = 23 g/mol

O = 16 g/mol x 1 = 16 g/mol

H = 1 g/mol x 1 = 1 g/mol

23 + 16 + 1 = 40g/mol

40 g/mol x 2 mols = 80 gramas

Al₂O₃

Al = 27 g/mol x 2 = 54 g/mol

O = 16 g/mol x 3 = 48 g/mol

54 + 48 = 102 g/mol

102 g/mol x 1,5 mol = 153 gramas

HNO₃

H = 1 g/mol x 1 = 1 g/mol

N = 14 g/mol x 1 = 14 /mol

O = 16 g/mol x 3 = 48 g/mol

48 + 14 + 1 = 63 g/mol

63 g/mol x 0,5 mol = 31,5 gramas

Ca(OH)₂

Ca = 40 g/mol x 1 = 40 g/mol

O = 16 g/mol x 2 = 32 g/mol

H = 1 g/mol x 2 = 2 g/mol

40 + 32 + 2 = 74 g/mol

74 g/mol x 10 mols = 740 gramas

Abraços!