Question

PRECISO DE AJUDAAA COM ESSA QUESTÃO ALGUEM DE ALMA SOLIDARIA ??? <3

Answer 1

sen120° = sen(180° - 120°) = sen60° = √3/2
sen240° = -sen(240° - 180º) = - sen60° = -√3/2
sen330° = -sen(360° - 330°) = -sen30° = -1/2
sen180° = 0

senπ/4 = √2/2
sen5π/6 = sen(π - 5π/6) = senπ/6 = 1/2
senπ = 0
sen7π/6 = -sen(7π/6 - π) = - senπ/6 = -1/2

a) √3[√3/2 - (-√3/2)] /-1/2 -0 = (3/2 + 3/2)(-2) = 6/2(-2) =3.(-2) = -6
b) (√2.√2/2 - 1/2)/) -1/2 = (1 - 1/2) .(-2)= 1/2 (-2) = -1