Question

Efetue, demonstrando o cálculo:
$\sqrt{ \sqrt{6}- \sqrt{2} } * \sqrt{ \sqrt{6}+ \sqrt{2} }$

Answer 1

Boa tarde!

$\sqrt{\sqrt{6}-\sqrt{2}}\cdot\sqrt{\sqrt{6}+\sqrt{2}}\\ \sqrt{\left(\sqrt{6}-\sqrt{2}\right)\cdot\left(\sqrt{6}+\sqrt{2}\right)}\\ \sqrt{\left(\sqrt{6}\right)^2+\sqrt{6}\sqrt{2}-\sqrt{2}\sqrt{6}-\left(\sqrt{2}\right)^2}\\ \sqrt{6-2}=\sqrt{4}=2$

Espero ter ajudado!