Question

considere a p.g (a) de razao q=√3 e a¹5= 5 determine a¹

Answer 1

Termo geral da PG
$an=a1.q^{n-1 }$

$a15=a1. \sqrt{3}^{15-1}$

$5=a1. \sqrt{3}^{14}$

$5=a1.{3}^{ \frac{1}{2}14}$

$5=a1.{3}^{7}$

$a1.{3}^{7} = 5$

$a1.= \frac{5}{3^7}$

$a1= \frac{5}{2187}$

Answer 2

a1q^14  = 5
q = V3
a1*( v3)^14  =5
2187a1 = 5
a1 = 5/2187 = 

NOTA
V3)^14 =  (V3)² * (V3)² * ( V3)² * (v3)² * (v3)² * (v3)² * (v3 )² = 3*3*3*3*3*3*3 =  2187