Question

resolva a questão de fatoriais:
6!
4!+3!



me ajudem gente

Answer 1

$\dfrac{6!}{4!+3!}= \dfrac{6 \cdot 5 \cdot 4 \cdot 3!}{4 \cdot 3!+3!} = \dfrac{6 \cdot 5 \cdot 4 \cdot \not 3!}{\not 3! \cdot (4+1)} = \dfrac{120}{5} = \boxed{\boxed{24}}$

Answer 2

Ola Shirley

6! = 1*2*3*4*5*6 = 720

4! + 3! = 24 + 6 = 30 

720/30 = 24