Question

Ajuda
-X²+3x+10
Eqçao de 2grau

Answer 1

-x²+3x+10=0
a=-1. b=3. c=10
delta=∆
∆=b²-4ac
∆=3²-4.(-1).10
∆=9+40
∆=49
x=-b±√∆/2a
x=-3-7/2.(-1)
x=-10/-2
x=5
x=-3+7/2.(-1)
x=4/-2
x=-2
S={(-2 ; 5)}

Answer 2

Ola Andre

-x² + 3x + 10 = 0

a = -1
b = 3
c = 10

delta
d² = b² - 4ac
d² = 9 - 4*(-1)*10 = 49
d = 7

x1 = (-b + d)/2a = (-3 + 7)/-2 = -2
x2 = (-b - d)/2a = (-3 - 7)/-2 = 5